SunExpress XQ778
Elazig — Hanover
| EZS |
Distance: 2743 km. / 1704 miles
|
HAJ |
|
|
|
| Usual departure time |
|
Usual arrival time |
| 21:55 |
|
01:15 |
Operating days: Thu. Usual times and days are based on observations in 2021. The schedule may have changed.
Flight status XQ778
Flight
SunExpress XQ778 (Elazig — Hanover) running from the airport
Elazığ Airport (EZS), to the airport
Hannover Airport (HAJ). The flight is operated by the family's aircraft Boeing 737-800. Flight distance is
2743 km / 1480 miles, and the average flight length is
4 h. 20 min..
Common questions about flight XQ778
What time does flight XQ778 depart?
Scheduled departure is 21:55 and arrival 01:15, local time at each airport. Operating days: Thu.
How long does flight XQ778 take?
On average 4 h 20 min. The airports are 2743 km / 1480 miles apart.
Which aircraft operates flight XQ778?
The flight is operated by the family's aircraft Boeing 737-800.
Low Price Calendar Elazig — Hanover
Types of aircraft flying XQ778 SunExpress: Elazig — Hanover
This section contains information about the types of aircraft and flight numbers that perform the flight. Based on observations in 2021.
Other flights on the route Elazig — Hanover
|
Flight No. |
Departure time* |
Arrival time* |
Aircraft |
 | XG1794 | 22:25 | 01:35 | Boeing 737-800 |
* Local time
All data is taken from open sources. The administration of the portal is not responsible for the accuracy of the information. For exact flight information, see the airline's website or the airport's website.