Flight G4605 Allegiant Air: Bloomington — Orlando Sanford International Airport


Allegiant Air

Allegiant Air G4605

Bloomington — Orlando Sanford International Airport

Usual departure time Usual arrival time
09:36 12:48
Operating days: Sun. Usual times and days are based on observations in 2017–2018. The schedule may have changed.

Flight status G4605



Flight Allegiant Air G4605 (Bloomington — Orlando Sanford International Airport) running from the airport Central Illinois Regional Airport at Bloomington-Normal (BMI), to the airport Orlando Sanford International Airport (SFB). The flight is operated by the family's aircraft Boeing (Douglas) MD-80, Airbus А320. Flight distance is 1477 km / 797 miles, and the average flight length is 2 h. 14 min..

Common questions about flight G4605


What time does flight G4605 depart?

Scheduled departure is 09:36 and arrival 12:48, local time at each airport. Operating days: Sun.

How long does flight G4605 take?

On average 2 h 14 min. The airports are 1477 km / 797 miles apart.

Which aircraft operates flight G4605?

The flight is operated by the family's aircraft Boeing (Douglas) MD-80, Airbus А320.


Low Price Calendar Bloomington — Orlando Sanford International Airport



Types of aircraft flying G4605 Allegiant Air: Bloomington — Orlando Sanford International Airport


Boeing (Douglas) MD-80
75%
Airbus А320
25%

Other flights on the route Bloomington — Orlando Sanford International Airport


Flight No. Departure time* Arrival time* Aircraft
G4215320:2623:42Airbus A319


Aircraft


Boeing (Douglas) MD-80
Boeing (Douglas) MD-80

Airports


[BMI] Central Illinois Regional Airport at Bloomington-Normal
+22.1 C 769 mm Hg. 39%
[SFB] Orlando Sanford International Airport
+31.6 C 761 mm Hg. 67%

Route


Bloomington — Orlando Sanford International Airport

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