Flight AF3658 Air France: Brussels — New York


Air France

Air France AF3658

Brussels — New York

Usual departure time Usual arrival time
11:00 13:25
Operating days: Fri. Usual times and days are based on observations in 2018–2021. The schedule may have changed.

Flight status AF3658



Flight Air France AF3658 (Brussels — New York) running from the airport Brussels Airport (BRU), to the airport John F Kennedy International Airport (JFK). The flight is operated by the family's aircraft Boeing 767-400. Flight distance is 5885 km / 3176 miles, and the average flight length is 8 h. 25 min..

Common questions about flight AF3658


What time does flight AF3658 depart?

Scheduled departure is 11:00 and arrival 13:25, local time at each airport. Operating days: Fri.

How long does flight AF3658 take?

On average 8 h 25 min. The airports are 5885 km / 3176 miles apart.

Which aircraft operates flight AF3658?

The flight is operated by the family's aircraft Boeing 767-400.


Low Price Calendar Brussels — New York



Types of aircraft flying AF3658 Air France: Brussels — New York


Boeing 767-400
100%

Other flights on the route Brussels — New York


Flight No. Departure time* Arrival time* Aircraft
KL614111:0013:25Boeing 767-400
DL14111:0013:25Boeing 767-400
LH562010:3513:00Airbus А330-300
SN50110:3513:00Airbus А330-300
TG651210:3513:00Airbus А330-300
UA992910:3513:00Airbus А330-300


Aircraft


Boeing 767-400
Boeing 767-400

Airports


[BRU] Brussels Airport
+10.1 C 771 mm Hg. 83%
Delays:
Low
[JFK] John F Kennedy International Airport
+16 C 773 mm Hg. 58%
Delays:
Low

Route


Brussels — New York

Flight rating


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